My English maths expressions are not up to scratch, and I know there are others who know much better than I do, but this is what I remember from my schooldays:
Loads wired in series add up, like (R1 + R2).
Loads wired in parallel go like (1/R1 + 1/R2) and then you turn the resulting fracture on its head and you have the end result. Loads wired in series, as a branch of a parallel load, are regarded as a single load.
If you put the 4 ohm cabs in series, and wire that in parallel with the 8 ohm cab, you get:
1/(4+4) + 1/8 = 1/8 + 1/8 = 2/8, make that 8/2 - that's 4 ohms.
If you put the 3 cabs in parallel, you get
1/4 + 1/4 + 1/8 = 2/8 + 2/8 + 1/8 = 5/8, make that 8/5 - that would be 1.6 ohm, not 8 ohm.
Hollis is right that Mike's formula (R1xR2xR3)/(R1+R2+R3) translates to (8x4x4)/(8+4+4) = 128/16 = 8 ohm - but I just don't know if that's the appropriate formula.